Sequence Number count
1. seq97016456712017-05-11 1
2 .seq97016456712017-05-11 1
3. seq97016456712017-05-12 2
4. seq97016456712017-05-12 2
How to generate the sequence based on the sequence Number if the sequence number is same the count should remain the same .How to do that ?
add 2 var Var1 and Var2.
fill seqnumber into the second var (Var2)
fill the first Var1 with if Var2 != seqnumber then Add 1 else add 0
Something like: (Var.var2==rowX.seqNumber)?Var.var1:Var.var1+1)
Don't forget to tag when it's "solved"!
One way of achieving this would be using a combination of tSortRow -- tMap. In tMap we basically have to store the previous row value and compare it against the current row value and derive the count.
Sample Job Flow -
Sample data -
tMap logic -
There is an easy way of doing this with a tMap, using your sequence number. Your sequence is a String and therefore you can use it as the sequence name for the routines.Numeric.sequence(seqName, startValue, step) routine method. So in your tMap you would create a tMap variable with this code in it....
routines.Numeric.sequence(row1.seqNum, 0, 1)
I've assumed your sequence number is in a row called "row1" and a column called "seqNum".
Hi @rhall_2_0 - I am just trying to understand your suggested method. If I am not wrong by putting a Numeric.sequence on SequenceNumber would result an incremented number being generated for every record and it would start from zero again for any new SequenceNumber.
Hi @rhall_2_0 ,
I have Done the same using a user routine for getting the distinct count based on some field and i have completed that.